Question 803733
The first step is to distribute the [3(z-120)].  

3(z-120) = (3*z)-(3*120) = 3z-360

Now the equation is 2/(3z-360) = 40.

The next step is to multiply each side by (3z-360).

(3z-360)*2/(3z-360) = 40*(3z-360)

In (3z-360)*2/(3z-360) the (3z-360)'s cancel out leaving you with 2=40*(3z-360).  Now muliply it out.

40*(3z-360) = (40*3z)-(40*360) = 120z-14,400

You now have 2=120z-14,400.  Add 14,400 to each side of the equation.

2+14,400 = 120z-14,400+14,400 The -14,400 and the +14,400 cancel out, leaving you with 120z.

The new equation is 14,402 = 120z.  Divide each side by 120.

14,402/120 = 120z/120

Round your answer to the nearest ones place.

z=120