Question 803202
{{{9(a + 2) * 72/(8(a^2 + 3a + 2))=(9(a + 2)/(a^2 + 3a + 2))(72/8)}}}
= {{{(9(a + 2)/(a^2 + 3a + 2))*9=81(a + 2)/(a^2 + 3a + 2)}}}
= {{{81(a + 2)/((a+1)(a+2))=(81/(a+1))((a+2)/(a+2))=highlight(81/(a+1))}}}
(As long as {{{a+2<>0}}} <---> {{{a<>-2}}} , of course).