<PRE><B>Question 802949</B>
A car leaves for Sacramento for Los Angeles traveling 54 mi/hr. A half hour later another car leaves Sacramento for Los Angeles traveling 64 mi/hr. How long after the second car leaves will it pass the first car?


Let the distance they meet at from Sacramento be x

Car I t= x/54

Car II t= x/64

Time taken by Car I - time taken by Car II = 1/2

x/54-x/64=1/2

64x-54x=54*64/2

10x=54*32
10x = 1728
/10
x=172.8

t= d/r

t= 172.8/64
=2.7 hours

Car II will meet after 2.7 hours</PRE>