Question 802669
Let J = John's age now
Let D = his daughter's age now
So right now J = 2D
In 4 years John will be J+4
His daughter's age 3 years ago is D-3
The equation is
J+4 = 3(D-3) [John 4 years from now is 3 times his daughter 3 years ago]
But since J = 2D, we have
2D + 4 = 3(D - 3)
Solve for D:
2D + 4 = 3D - 9
This gives D = 13
So right now, daughter is 13 and John is 26.