<PRE><B>Question 802379</B>
A private airplane leaves Midway airport and flies due east at a speed of 180km/h.
 Two hours later, a jet leaves and flies due east at a speed of 900km/h.
 How far from the airport will the jet overtake the private plane?
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I would do it this way.
Let t = time required for the jet to overtake the slower plane
then
(t+2) = travel time of the slower plane when overtaken
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When this happens they will have traveled the same distance
Write a dist equation: dist = speed * time
;
900t = 180(t+2)
900t = 180t + 360
900t - 180t = 360
720t = 360
t = 360/720
t = .5 hrs, a half hour for the jet to overtake the slower plane
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Now find the distance
900 * .5 = 450 mi
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Confirm this solution by finding the distance with the slower plane
2.5(180) - 450 mi also </PRE>