Question 802569
Radius of the sphere is {{{(1/2)6=3}}} cm.
VOLUME is {{{(4/3)pi*3^3}}} cubic centimeters, the same as would be the 0.10 cm diameter rod.


Let y = the length of the rod formed, its volume is {{{pi*(1/2)0.1*y}}} {{{cm^3}}}


Form the equation {{{(4/3)pi*3^3=pi*0.05y}}},
Simplify and solve for y.
{{{4*pi*3^2=pi*0.05y}}}
{{{4*3^2=0.05y}}}
.
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The solution used radius as "half of diameter is radius".