Question 802271
Let r = inside radius of the pipe, cm
Let h = height (length) of the pipe, cm
Let B = inside area of the end of the pipe, cm^2
Let V = the volume of the pipe, cm^3
Use the formula
(1) V = B*h or
(2) {{{V = (pi*r^2)*h}}}
The inside diameter is the outside diameter of 12cm minus twice the thickness, 0.5cm, of the pipe. The inside radius is one half of the inside diameter or
(3) r = (12-2*0.5)/2 or
(4) r = (12-1)/2 or
(5) r = 11/2 or
(6) r = 5.5
The area of the pipe's cross-section is
(7) {{{B = pi*r^2}}} or
(8) {{{B = pi*5.5^2}}} or
(9) {{{B = pi*30.25}}}
The height, h, of the pipe is the same as the length or 2.4m, which converts to 240cm (all length units must be the same). Substituting B and h into (1) yields
(10) {{{V = pi*30.25*240}}} or
(11) {{{V = pi*7260 cm^3}}} or
(12) {{{V = 22808cm^3}}} or
(13) {{{V = 0.0228m^3}}}