Question 801955


if you have {{{21x/2 = 2(x-1) + 3}}}, than first multiply {{{2(x-1)}}}

{{{21x/2 = 2x-2 + 3}}}

{{{21x/2 = 2x  + 1}}}..now both sides multiply by {{{2}}}

{{{2(21x/2) = 2(2x  + 1)}}}

{{{cross(2)(21x/cross(2)) = 4x  + 2}}}

{{{ 21x  = 4x  + 2}}}......add {{{-4x}}} to both sides

{{{ 21x -4x = 4x-4x  + 2}}}

{{{ 17x = 2}}}

{{{  x = 2/17}}}