Question 68061
Let l = the length and W = the width of the rectangle.  From the problem description, you can write:
{{{L = 2W+2}}}
The perimeter, P, of a rectangle is given by:
{{{P = 2L + 2W}}} Substitute the L from above and P = 52 and solve for W.
{{{52 = 2(2W+2) + 2W}}}
{{{52 = 4W+4 + 2w}}}
{{{52 = 6W+4}}} Subtract 4 from both sides.
{{{48 = 6W}}} Divide both sides by 6.
{{{8 = W}}} 
The width is 8 cm
{{{L = 2W+2}}}
{{{L = 2(8)+2}}}
{{{L = 16+2}}}
{{{L = 18}}}
The length is 18 cm

Check:
{{{P = 2L+2W}}}
{{{P = 2(18)+2(8)}}}
{{{P = 36+16}}}
{{{P = 52}}}