<PRE><B>Question 801853</B>
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If you want an average score of *[tex \Large \geq\,\mu] for *[tex \Large n] tests, then the sum of all your tests must be *[tex \Large \geq\,\mu\,\cdot\,n].  Then *[tex \Large g\ \geq\ \mu\cdot n\ -\ \sum_{k\,=\,1}^{n\,-\,1}\,s_k]  where *[tex \Large s_1] through *[tex \Large s_5] are the scores on the first five tests. 


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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