Question 801726
{{{3sqrt(2)/(2sqrt(3)-5sqrt(2))=3sqrt(2)(2sqrt(3)+5sqrt(2))/(2sqrt(3)-5sqrt(2))/(2sqrt(3)+5sqrt(2))=
(3sqrt(2)*2sqrt(3)+3sqrt(2)*5sqrt(2))/((2sqrt(3))^2-(5sqrt(2))^2)=
(3*2sqrt(2)sqrt(3)+3*5sqrt(2)sqrt(2))/(2^2*3-5^2*2)=(6sqrt(2*3)+15*2)/(12-50)
=(6sqrt(6)+30)/(-38)=-(15+3sqrt(6))/19}}}
 
NOTES:
{{{3sqrt(2)/(2sqrt(3)-5sqrt(2))}}} can be typed as
3sqrt(2) / ( 2sqrt(3) - 5sqrt(2) )
for the understanding of people and this website.
People may even understand you if you "abbreviate" it as
3sqrt2 / ( 2sqrt3 - 5sqrt2 ),
but you still need the entire denominator wrapped in brackets.
 
Calculators and computers will require asterisks for the usually omitted multiplication signs, so you would have to enter
3*sqrt(2) / ( 2*sqrt(3) - 5*sqrt(2) )
 
If there are plus and minus signs in your numerator and/or denominator, you need to wrap it/them in brackets, because
3(sqrt(2))/2(sqrt(3))-5(sqrt(2)) = {{{3(sqrt(2))/2(sqrt(3))-5(sqrt(2))}}}
If you ask a calculator for
0.735-0.002/0.728-0.003 = {{{0.735-0.002/0.728-0.003=0.729}}} (rounded)
most calculators will give you exactly what you ask for.
They will not understand that you mean
(0.735-0.002)/(0.728-0.003) ={{{(0.735-0.002)/(0.728-0.003)}}}