<PRE><B>Question 801768</B>
Find two consecutive integers such that the sum of the three fifths of the first and one fourth of the second is 13?
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let x=1st consecutive integer
x+1=2nd consecutive integer
..
(3/5)x+(1/4)(x+1)=13
{{{3x/5+(x+1)/4=13}}}
LCD:20
12x+5(x+1)=20*13
12x+5x+5=260
17x=255
x=255/17=15
x+1=16
1st consecutive integer=15
2nd consecutive integer=16</PRE>