Question 67971
find three consecutive odd integers
x, (x+2), (x+4)
:
 such that 9 times the first is the same as the sum of 3 times the second and 4 times the third.
:
9x = 3(x+2)+4(x+4)
:
9x = 3x + 6 + 4x + 16
:
9x = 7x + 22
:
9x - 7x = 22
:
2x = 22
:
x = 11
:
:
Check: 9(11) = 3(13) + 4(15) 
99 = 39 + 60