<PRE><B>Question 801297</B>
In a statistics class with 15 males and 13 females, five students are selected to put problems on the board. What is the probability that: 
a. 3 females and 2 males are selected?
# of ways to succeed = 13C3*15C2
# of possible groups of 5 = 28C5
P(3 fem and 2 male) = 30030/98280 = 0.3056 
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b. P(all five students selected are males?) = 15C5/28C5 = 0.0306
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c. all five students selected are females? 
Ans: 13C5/28C5
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Cheers,
Stan H.


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