<PRE><B>Question 801287</B>
  2x^2-2x-1=0. 
The available answers all contain imaginary numbers. (A) 1+i (B)1/2 plus or minus i (C) 2+3i (D) 1/2 plus or minus 1/2i
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Formula:
x = [-b+-sqrt(b^2-4ac)]/(2a)
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Your Problem:
x = [2 +- sqrt(4-4*2*-1)]/(4)
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x = [2 +- sqrt(12)]/4
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x = [2 +- 2sqrt(3)]/4
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x = (1/2) +- (1/2)sqrt(3)
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Cheers,
Stan H.
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