Question 801274
let’s three numbers be {{{x}}}, {{{y}}}, {{{z}}} 

given:

{{{x+y+z=62}}}

the second is 5 more than the smallest => {{{y=x+5}}}

the third is 8 less than the second =>{{{ z=y-8}}} or {{{z=(x+5)-8=x-3}}}

{{{x+y+z=62}}} ....substitute {{{y=x+5}}} and {{{z=x-3}}}

{{{x+x+5+x-3=62}}}
{{{3x+2=62}}}
{{{3x=62-2}}}
{{{3x=60}}}
{{{highlight(x=20)}}}

{{{y=x+5 }}} => {{{highlight(y=25)}}}

 and 

{{{z=x-3}}}=>{{{highlight(z=17)}}}