<PRE><B>Question 801159</B>
A rectangle has a width 4cm less than the length. 
Length = L
Width = L-4
========================
If a new rectangle is formed by increasing the width 5cm and decreasing the length 3cm, the area of this resulting rectangle is 117cm^2.
Length = L-3
Width = L-4+5 = L+1
========================
Equation:
Area = length * width
117 = (L-3)(L+1)
L^2 -2L -3 = 117
L^2 -2L - 120 = 0
--
Factor:
(L-12)(L+10) = 0
Positive solution:
L = 12 cm (original length)
---
W = L-4 = 8 cm (original width)

 What are the dimensions of the original rectangle?

========================
Cheers,
Stan H.
========================</PRE>