Question 801130
4x=3(4-y)
2y=4(3-x)
first step is to put each equation in standard form y = mx +b
1)4x=3(4-y)
4x = 12 -3y
-3y = 4x - 12
y = -4x/3 +4
2)2y=4(3-x)
2y = 12 -4x
y = -2x +6
now we can graph the following two equations
y = -4x/3 +4
y = -2x +6
{{{ graph( 300, 200, -10, 10, -10, 10, -4x/3 +4,-2x+6) }}}
now you can see that the intersection point is (3, 0)