<PRE><B>Question 801027</B>
An arrow is shot upward from a platform of 20ft high with an initial velocity of 184 ft per second. Its height(h)in ft after t seconds is given by: h= 16t squared +184+20. When will the arrow be 50 ft above the ground?
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h(t) = -16t^2 +184t + 20
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Solve:: -16t^2 + 184t + 20 = 50
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-16t^2 + 184t - 30 = 0
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-8t^2 + 92t - 15 = 0
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t = 11.3246 seconds
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Cheers,
Stan H.
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