Question 800970
 Please help me solve this equation:
y = 3x-3
y = {{{y^2-2x}}}
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It's 2 equations.
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Sub for y in the 2nd equation
{{{3x-3 = (3x-3)^2 - 2x}}}
{{{9x^2 - 20x + 9 = 3x-3}}}
{{{9x^2 - 23x + 12 = 0}}}
*[invoke solve_quadratic_equation 9,-23,12]
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y = 3x - 3 for 2 values of x.