Question 800934
{{{(3r-2)^2-28=0}}}


{{{(3r-2)^2=28}}}

take the square root

3r-2 = +/- sqrt(28)

3r = 2+/- sqrt(28)

r= (2+/- 2sqrt(7))/3

r= (2/3) (1+/- sqrt(7))