Question 800834
I could not quite follow what you did here, anyway:
:
Divide and express in standard form 2/3-i 
{{{2/((3-i))}}}*{{{((3+i))/((3+i))}}} = {{{(2(3+i))/((9 +3i - 3i -i^2))}}} = {{{((6+2i))/((9 - (-1)))}}} = {{{((6+2i))/((9 + 1)))}}} = {{{((6+2i))/(10)}}}
reduce the fraction, factor out 2
{{{((3+i))/5}}}