Question 800622
Find the equation in the general form of the circle through the points (5,1) , (4,6) and (2,-2)
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Label the points A(5,1), B(4,6) and C(2,-2)
Find the perpendicular bisectors of any 2, AB, AC or BC
Find the intersection of the the bisectors, that's the center of the circle.  Call it (h,k)
Find the distance from the center to any point A, B or C, that's the radius.
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The circle is {{{(x-h)^2 + (y-k)^2 = r^2}}}
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