Question 67942
The square root of 7/9 times the square root of 27/49. 
[sqrt(7/9)]*[sqrt(27/49]=sqrt[27*7] / sqrt[49*9]
=[3sqrt 21]/[7*3
=[sqrt21]/7
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Also another problem of the square root of 3/16 times the square root of 4/25 times the square root of 5/36.
[sqrt(3/16)]*[sqrt(4/25)]*[sqrt(5/36)]
=(1/4)(sqrt3)*(2/5)*(1/6)sqrt5
=(1/60)sqrt15
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Cheers,
Stan H.