Question 800398
Determine the equation of the circle defined by the given conditions
a) (5,1) and (-3,3) are endpoints of a diameter 
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equation of circle: (x-h)^2+(y-k)^2=r^2
To find center:
Use midpoint formula:(x1+x2)/2,(y1+y2)/2, with end points
=(5-3)/2,(1+3)/2=(1,2)=(x,y) coordinaes of center
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Distance formula: d^2=(x1-x2)^2+(y1-y2)^2
to find radius, use distance formula with coordinates of center(1,2) and one endpoint(-3,3)
r^2=(-3-1)^2+(3-2)^2=16+1=17
equation of circle: (x-1)^2+(y-2)^2=17