Question 800435
Not really about Complex Numbers the way you categorized your exercise problem.


Both sides have term, {{{3x^2}}}, so just subtract this from both sides.
You then have {{{-(2x-4)=1}}},
{{{-2x+4=1}}}
{{{2x-4=-1}}}
{{{2x=-1+4}}}
{{{2x=3}}}
{{{x=3/2}}}