Question 800241
Assuming order doesn't matter, then...


n C r = (n!)/(r!(n-r)!)


5 C 3 = (5!)/(3!*(5-3)!)


5 C 3 = (5!)/(3!*2!)


5 C 3 = (5*4*3!)/(3!*2!)


5 C 3 = (5*4)/(2!)


5 C 3 = (5*4)/(2*1)


5 C 3 = (20)/(2)


5 C 3 = 10


Assuming order doesn't matter, then there are <font color="red">10</font> different ways to do this.