Question 800141
A point whose abscissa and ordinate are equal is square root of 10 units from (-1, -3). find the two possible points.
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{{{(x+1)^2 + (y+3)^2 = 10}}} is a circle, all the points sqrt(10) from the given point.
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{{{(x+1)^2 + (y+3)^2 = 10}}}
x = y
{{{(x+1)^2 + (x+3)^2 = 10}}}
{{{2x^2 + 8x = 0}}}
x = 0, x = -4
--> (0,0), (-4,-4)