<PRE><B>Question 799691</B>
 Ed can do a job in 4 days.
 When Ed and Maymay work together, it would take them 2 1/3 days.
 How long would the job take Maymay to do the job alone?
:
Let m = May^2 time to do the job alone
let the completed job = 1
Change 2 1/3 days to 7/3
:
A shared work equation
{{{(7/3)/4}}} + {{{(7/3)/m}}} = 1
Which is
{{{7/12}}} + {{{7/(3m) }}} = 1
multiply by 12m, resulting in
7m + 4(7) = 12m
28 = 12m - 7m
28 = 5m
m = 28/5
m = 5{{{3/5}}} days May^2 alone
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