Question 799415
Find the equation in the form of y=mx+b through (2,2), perpendicular to y=3x+4.
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Equation of a line: y=mx+b, m=slope, b=y-intercept
given equation:y=3x+4
slope,m=3
slope of line perpendicular to given line=-1/3(negative recprocal)
Equation:y=-x/3+b
solve for b using coordinates of given point(2,2)
2=-2/3+b
b=2+2/3=8/3
equation of perpendicular line:
y=-x/3+8/3