<PRE><B>Question 799609</B>
Find the equation of a line with the given information: 
f(-13) = 6 and perpendicular to 32x+40y=38 
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40y = -32x + 38
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y = (-4/5)x + (38/40)
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slope = -4/5
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The perpendicular line must have slope = 5/4
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Find equation of line with slope = 5/4 passing thru (-13,6)
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y = mx + b
6 = (5/4)(-13) + b
24/4 = -65/4 + b
b = 89/4
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Equation:
y = (5/4)x + (89/4)
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Cheers,
Stan H.
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