Question 799310
What is the cotangent of theta and secant of theta if sin of theta=1/3, tangent of theta <0
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sinx=1/3
reference angle in quadrant II where sin>0,tan<0,cos<0
cosx=-&#8730;(1-sin^2x)=-&#8730;(1-1/9)=-&#8730;(8/9)=-&#8730;8/3
tanx=sinx/cosx=-1/&#8730;8=-&#8730;8/8
cotx=1/tanx=-&#8730;8
secx=1/cosx=-3/&#8730;8=-3&#8730;8/8