<PRE><B>Question 799449</B>
&lt;font face=&quot;Times New Roman&quot; size=&quot;+2&quot;&gt;


If it takes L *[tex \Large x] hours to do 1 whole job, he can do *[tex \Large \frac{1}{x}] of the job in 1 hour.  Likewise, if it takes P *[tex \Large 2x] hours, then he can do *[tex \Large \frac{1}{2x}] of the job in 1 hour.  Together they take 20 hours, so together they can do *[tex \Large \frac{1}{20}] of the job in one hour.


So


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{1}{x}\ +\ \frac{1}{2x}\ =\ \frac{1}{20}]


Solve for *[tex \Large x] to get L&#39;s time, *[tex \Large 2x] to get P&#39;s time.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
&lt;div style=&quot;text-align:center&quot;&gt;&lt;a href=&quot;http://outcampaign.org/&quot; target=&quot;_blank&quot;&gt;&lt;img src=&quot;http://cdn.cloudfiles.mosso.com/c116811/scarlet_A.png&quot; border=&quot;0&quot; alt=&quot;The Out Campaign: Scarlet Letter of Atheism&quot; width=&quot;143&quot; height=&quot;122&quot; /&gt;&lt;/a&gt;&lt;/div&gt;
&lt;/font&gt;</PRE>