Question 798998
"Suppose you wish to mix 10% acid solution with 24% acid solution to make 10 liters of 14% acid solution.
 How many liters of each solution should you use?" 
:
Do it this way,
Let x = amt of 24% solution
then total amt is to e 10 l, therefore
(10-x) = amt of 10% solution
:
A simple mixture equation
.24x + .10(10-x) = .14(10)