<PRE><B>Question 798977</B>
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*[tex \LARGE \sqrt{k\ +\ 3}] represents the positive square root.  Therefore the LHS of your equation is greater than zero for all *[tex \LARGE k] in the domain of the left-hand function.  The solution set is the null set.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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