<PRE><B>Question 798932</B>
1 quarter = $0.25
1 dime = $0.10
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Set up:
Let A = number of quarters
Let B = number of dimes
Equation 1: {{{B = 3A + 11}}}
Equation 2: {{{0.25*A + 0.10*B = 4.95}}}
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Solution:
Since equation one is solved for B, Plug (3A + 11) into equation 2 for B.
Equation 2: {{{0.25*A + 0.10*B = 4.95}}}
{{{0.25*A + 0.10*(3A + 11) = 4.95}}}
Multiply the 0.10 trhough.
{{{0.25A + 0.3A + 1.1 = 4.95}}}
Combine like terms.
{{{0.55A + 1.1 = 4.95}}}
Subtract 1.1 from both sides.
{{{0.55A = 3.85}}}
Divide both sides by 0.55
{{{highlight(A = 7)}}}
Now plug 7 into equation 1 for A.
Equation 1: {{{B = 3A + 11}}}
{{{B = 3*(7) + 11}}}
{{{B = 21 + 11}}}
{{{highlight_green(B = 32)}}}
Annie has 32 dimes.</PRE>