Question 798717
A.     Jason and Steve are 45 miles apart on the canal riding toward each other. Steve is twice as fast as Jason. They meet up after 2 hours. How fast is Steve?
------------
Their speeds are added when going in opposite directions.
45 mi/2 hr = 22.5 mi/hr
J = Jason's speed
S = Steve's speed
J + S = 22.5
S = 2J
---
J + 2J = 22.5
J = 7.5 mi/hr
S = 15 mi/hr
===========================
B.     after they meet up, Jason heads home. 15 minutes later, Steve leaves to catch up. How long was Jason biking when Steve caught up?
---
Assuming they go at the same speeds:
In 15 minutes Jason goes 7.5*0.25 miles = 15/8 miles.
-----
Steve "gains on" him at 7.5 mi/hr (15 - 7.5)
d = r*t
t = d/r = (15/8)/(15/2) = 1/4 hour to catch up.
Jason was biking 15 + 15 = 30 minutes

I drew a table and figured one equation was x+y=45 but I cannot find the other equation. I also tried using D=RT.