Question 67834
Need help! Studying for my final exam and unable to comprehend the following from quiz given.
1. Give the center of the circle with equation x2+2x+y2-10y+22=0.
(X+1)^2-1^2+(Y-5)^2-5^2+22=0
HENCE THE CENTER OF CIRCLE IS (-1,5)
2. Find an equation for the line with slope 1/2 and y-intercept 3.
Y=(1/2)X+3=0.5X+3
3. Find the slope of the line through the points A(-1, 6) and B(5, 2).
SLOPE=(2-6)/(5+1)=-4/6=-2/3
4. Find an equation for the line with y-intercept 3that is perpendicular to the line y=2/3 x-4.
SLOPE OF PERPENDICULAR LINE =-3/2.........HENCE EQN.OF LINE IS
Y=(-3/2)X+3=-1.5X+3
5. If f(x)=x2+5, find f(a+h)-f(a). 
F(A+H)=(A+H)^2+5
F(A)=A^2+5
F(A+H)-F(A)=(A+H)^2-A^2=H^2+2AH