Question 798486

The length of a rectangle is five times its width. If the perimeter is at most 96 centimeters, what is the greatest possible value for the width?


Let width be W


Then length = 5W


Therefore, {{{2(W + 5W) <= 96}}}


{{{2(W + 5W) <= 2(48)}}}


{{{W + 5W <= 48}}}


{{{6W <= 48}}}


Width, or {{{W <= 48/6}}}, or {{{W <= 8}}}


Greatest possible width: {{{highlight_green(8)}}} cm


You can do the check!! 


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