Question 798464
<pre>

y &#8806; |x-6|

First we draw the graph of the boundary which is

y = |x-6|

It is a V-shaped graph with vertex (6,0). We draw it solid
(not dotted) because the inequality &#8806; tells us that we are 
to include the boundary as part of the solution set.

{{{drawing(400,800/3,-3,15,-3,9, graph(400,400,-3,15,-9,9,y=abs(x-6)),
blue(line(6,0,21,15),

line(6,0,-21,27)),


 graph(400,800/3,-3,15,-3,9))}}}

We use the origin as a test point:

Substituting in the original inequality:

y &#8806; |x-6|
0 &#8806; |0-6|
0 &#8806; |-6|
0 &#8806; 6

That is true so (0,0) is a solution and so
all the solutions are on the same side of the graph
that (0,0) is on.  So we shade that side of the
boudary:

{{{drawing(400,800/3,-3,15,-3,9, graph(400,400,-3,15,-9,9,y=abs(x-6),y=abs(x-6)+.05,y<abs(x-6)+.1), 
graph(400,400,-3,15,-9,9,23,24,25,26,27, y<abs(x-6)),graph(400,800/3,-3,15,-3,9))}}}


Edwin</pre>