Question 798463
how much of an alloy that is L% copper should be mixed with V ounces of an alloy that is H% copper in order to get an alloy that is T% copper?


Very typical two-part mixture problem.


Let u = ounces of the L% alloy.
L = 20% Cu
T = 30% Cu
H = 60% Cu
V = 600 ounces of the 60% alloy


{{{highlight((Lu+HV)/(u+V)=T)}}}
Solve for u.
Substitute the given values to find the value for u.