Question 798450
Use the quadratic formula to solve for x


{{{x = (-b+-sqrt(b^2-4ac))/(2a)}}}


{{{x = (-(-4)+-sqrt((-4)^2-4(1)(5)))/(2(1))}}} Plug in {{{a = 1}}}, {{{b = -4}}}, {{{c = 5}}}


{{{x = (4+-sqrt(16-(20)))/(2)}}}


{{{x = (4+-sqrt(-4))/2}}}


{{{x = (4+sqrt(-4))/2}}} or {{{x = (4-sqrt(-4))/2}}}


{{{x = (4+2*i)/2}}} or {{{x = (4-2*i)/2}}}


{{{x = 2+i}}} or {{{x = 2-i}}}



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The two solutions are {{{x = 2+i}}} or {{{x = 2-i}}} where {{{i=sqrt(-1)}}}