Question 798452
{{{8x^2 + 5x = -3}}}


{{{8x^2 + 5x + 3 = 0}}}


Use the quadratic formula to solve for x


{{{x = (-b+-sqrt(b^2-4ac))/(2a)}}}


{{{x = (-(5)+-sqrt((5)^2-4(8)(3)))/(2(8))}}} Plug in {{{a = 8}}}, {{{b = 5}}}, {{{c = 3}}}


{{{x = (-5+-sqrt(25-(96)))/(16)}}}


{{{x = (-5+-sqrt(-71))/16}}}


{{{x = (-5+sqrt(-71))/16}}} or {{{x = (-5-sqrt(-71))/16}}}


{{{x = (-5+i*sqrt(71))/16}}} or {{{x = (-5-i*sqrt(71))/16}}}


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The two solutions are


{{{x = (-5+i*sqrt(71))/16}}} or {{{x = (-5-i*sqrt(71))/16}}}