Question 798397
Find an equation of a circle satisfying the given conditions : center (-8,5) with circumference 10π units 
.
Standard form of an equation is:
(x - h)^2  +  (y-k)^2   =   r^2
where
(h,k) is the center
r is the radius
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The problem already gave you the center as (-8,5)
so already you know:
h = -8
k = 5
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You get the radius from the given circumference of 10(pi)
circumference = 2(pi)r
10(pi) = 2(pi)r
10 = 2r
5 = r (radius)
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Now, we just plug it in to:
(x - h)^2  +  (y-k)^2   =   r^2
(x - (-8))^2  +  (y-5)^2   =  5^2
(x+8)^2 + (y-5)^2 = 25  (answer)