Question 798336
The standard form of a line is y = mx +e  where m is the slope and e is the y intercept
we use the points (t, 2b) and (c, 3b) to calculate the slope
m = (3b -2b) / (c -t) = b / (c-t)
therefore y = bx/(c-t) +e
note that the slope of y = x+11 is 1 and
the slope of y  = -x+2 is -1
two lines are perpendicular if the product of their slopes are -1
these two lines are perpendicular