Question 764950
The answer is 9 not the 4 as solved by  MathLover1(7369).I guanrentee This!

The number on dividing by 5 leaves remainder 4.

Digitsum of Numbers (1234......424344)-->
The number are from 0 to 9 (Sum of digits 45) 
then 10 to 19 (Digit sum 45+1x10 = 55) 
then 20 to 29 (Digit sum 45+2x10 = 65) 
then 30 to 39 (Digit sum 45+3x10 = 75) and 
then 40 to 44 (digit sum (10+4x5 = 30) 
therefore total digit sum come out to be (45+55+65+75+30 = 270)
This is divisible by 9.

When the given number is divided by 5 it leaves a remainder 4. So the number is of the form 5A + 4. 
When divided by 9 it leaves a remainder 0. Hence of the form 9B+0.

Equate both the equations 5A+4=9B. 
Put A= 1 and B= 1 we get 9 which is the remainder.

Try Another Example:(Very Simple1):243/45 rem is not 3 isn't it?