Question 797632
Use the laws of logarithms to rewrite each expression as a single logarithm, do NOT evaluate.
1) log 4 + log 25
=log(4*25)
=log(100)
..
2)log(little 2) 4 - log (little 2) 2
{{{log(2,(4))-log(2,(2))=log(2,(4/2))=log(2,(2))}}}
..
3)4log(little 4) 2
{{{4log(4,(2))=log(4,(2^4))=log(4,(16))}}}
..
Evaluate your answers from problems above, show your setups (b^k=n).
1) evaluate solution to problem 1.log(100)=2
2)Evaluate solution to problem 2.{{{log(2,(2))=1}}}
3) evaliate solution to problem 3.{{{log(4,(16))=4}}}
4)5^x= 100 solve for x using logarithms (round to 3 decimal places.)
xlog(5)=log(100)
x=log(100)/log(5)=2/log(5)≈2.861