Question 797293
Solve log10(3x + 2) – 2log10x = 1 – log10(5x – 3)
{{{log((3x+2))-2log((x))=1-log((5x-3))}}}
{{{log((3x+2))-2log((x))+log((5x-3))=1}}}
{{{log((3x+2)(5x-3)/(x^2))=log(10)}}}
{{{((3x+2)(5x-3)/(x^2))=(10)}}}
(3x+2)(5x-3)=10x^2
15x^2+x-6=10x^2
5x^2+x-6=0
(5x+6)(x-1)=0
x=-6/5
or
x=1