Question 797830
"Find the shorter leg of a right triangle if the longer leg is 24 meters and the hypotenuse is 6 more than twice the shorter leg." 
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Shorter leg: x meters
Longer leg: x+24 meters
Hypotenuse: 2x + 6
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Solve::
x^2 + 24^2 = (2x+6)^2
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x^2 + 24^2 = 4x^2 + 24x + 36
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3x^2 +24x - 540 = 0
x^2 + 8x - 180 = 0
Positive solution:
x = 10
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Cheers,
Stan H.
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