Question 797786
Solve the system of equations.

y=2x^2-3
y=3x-1
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Solve for x & y
Since they both equal y, 
{{{2x^2 - 3 = 3x - 1}}}
{{{2x^2 - 3x - 2 = 0}}}
(2x + 1)*(x - 2) = 0
x = 2 --> y = 5   Answer #1
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x = -1/2 --> y = -5/2   Answer #2